[opencms-dev] Duplicate entry 'Guests' for key 2

[Stephan Hartmann]

Hi Andy,

you could look into your database to verify if there are two entries for 
group Guests in table CMS_GROUPS.

Start mysql as root on your OpenCms database:

# mysql opencms

now do a select

mysql> select * from CMS_GROUPS where GROUP_NAME="Guests";

if there are two you may delete one.

If you don't get any further i would suggest to try out the latest stable 
release until 5.0 becomes final.

Bye,
Stephan

 
Am Dienstag, 27. August 2002 10:40 schrieben Sie:
> Hi,
>
> I have installed opencms_5.0_beta_1.zip on RedHat 7.2 with
> mySql/Apache/Tomcat4/JBOSS
>
> The setup wizzard ran without errors, but when I try and login to start
> the workplace, I get the following Internal Server Error:
>
> javax.servlet.ServletException: [CmsException]: 33 Resourcebroker-init
> error. Detailed Error: Critical error while loading resourcebroker. .
> Caught Exception: >[CmsException]: 4 Sql exception. Detailed Error:
> [com.opencms.file.mySql.CmsDbAccess] Invalid argument value: Duplicate
> entry 'Guests' for key 2. Caught Exception: >java.sql.SQLException:
> Invalid argument value: Duplicate entry 'Guests' for key 2<<
> at com.opencms.file.CmsRbManager.init(CmsRbManager.java:98)
> at com.opencms.core.OpenCms.(OpenCms.java:184)
> at com.opencms.core.OpenCmsHttpServlet.init(OpenCmsHttpServlet.java:434)
> etc etc etc . . . .
>
> Does anybody know how to resolve this? Also is 5.0 Beta the latest
> stable release, or should I be using 4.7.7 ?
>
> Many thanks,
>
> Andy

-- 
Stephan Hartmann

Währisch & Feykes GmbH
Gustav-Adolf-Str. 5
47057 Duisburg
Tel. 0203 / 373 070
Fax 0203 / 376 766
hartmann at wfnetz.de

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